x^2-50x+175=0

Solution for x^2-50x+175=0 equation:

x^2-50x+175=0

a = 1; b = -50; c = +175;
Δ = b2-4ac
Δ = -502-4·1·175
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-30\sqrt{2}}{2*1}=\frac{50-30\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+30\sqrt{2}}{2*1}=\frac{50+30\sqrt{2}}{2}
$